The combustion of glucose is as followsc6h12o6 s 6o2 6co2, Ask an Expert

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The combustion of glucose is as follows:

C6H12O6 (s) + 6O2 ? 6CO2 (g) + 6H2O (l)

Assuming that none of the intermediates have appreciable concentrations, what are the values of d[C6H12O6]/dt, d[O2]/dt, d[CO2]/dt, and d[H2O]/dt, given that the overall rate is 1.0 x 10-4 mol·L-1s-1. Assume there is an excess of oxygen in the system.

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Category:- Chemistry
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