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Question. The collar C is moving downward with an acceleration of 1 m/s2. At the instant shown, it has a speed of 2 m/s which gives links CB and AB an angular velocity ωAB = ωCB = 10 rad/s. Find the angular accelerations of AB and CB at this instant.

Suggestions:

(A) Calculate aAB and aCB
(B) aB = aC + aB/C)t + aB/C)n
(C) aB/C)t = raCB
(D) aB/C)n = rωCB2

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Category:- Physics
Reference No.:- M9161763

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