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The amount of lactic acid,HC₃H₅O₃, produced in a sample ofmuscle tissue was analyzed by reaction with hydroxide ion.Hydroxide ion was produced in the sample mixture by electrolysis.The cathode reaction is given below.2 H₂O(l) + 2 e ‾→ H₂(g) + 2 OH ‾ (aq)Hydroxide ion reacts with lactic acid as soon as it is produced.The endpoint of the reaction is detected with an acid-base indicator. It required 106 s for a currentof 18.8 mA to reach the endpoint. How many grams of lactic acid (a monoprotic acid) were present in the sample?

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