(Answered) The first-order decomposition of n2o5 at 328 k has a rate

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The first-order decomposition of N2O5 at 328 K has a rate constant of 1.70 . 10-3 s-1. If the initial concentration of N2O5 is 2.88 M, what is the concentration of N2O5 after 12.5 minutes?

I already know the answer is .805M, but I'm not sure why my professor solved it the way he did:

ln [A] = -kt + ln [Ao]

ln [A] = (-1.70 x 10^-3 x 12.5 x 60) + ln (2.88)

Why is the temperature 60 instead of 328K?

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