(Answered) Suppose you add 4.25 g of naphthalene c10h8 to 67.9 g of

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Suppose you add 4.25 g of naphthalene, C10H8, to 67.9 g of benzene, C6H6, and they form an ideal solution. The vapor pressure of pure benzene is 0.1252 atm at the temperature of the experiment. What is the vapor pressure of the benzene above the solution?The molar mass of naphthalene is 128.17 g /?mole and the molar mass of benzene is 78.0 g /?mol.

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As per the question, we know that there are two different types of solute -volatile and non-volatile When we add volatile or non-volatile solute in any solvent there will be decrease in vapor pressure of solvent. so to measure the lowering of vapor pressure Raoults proposed a equation which explains the relation between Lowering of vapor pressure and mole fraction. I have applied this equation to find out the value.

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