Suppose we start with 0.0530 mol of n2o5 in a volume of 5.2, Ask an Expert

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The first-order rate constant for the decomposition of N2O5, 2 N2O5(g) 4 NO2(g) + O2(g) at 70 oC is k = 6.82e-03 s-1. Suppose we start with 0.0530 mol of N2O5 in a volume of 5.2 L. How many minutes will it take for the quantity of N2O5 to drop to 0.0253 mol? a) It will take 1.08e+02 minutes. b) It will take 5.04e-03 minutes. c) It will take 4.71e+01 minutes. d) It will take 1.81e+00 minutes. e) It will take 7.85e-01 minutes.

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