Q. Suppose the skin temperature of a naked person is 34 °C while the person is standing inside a room whose temperature is 25 °C. The skin area of the individual is 2 m2. (1) The emissivity is 0.80; find out the net loss of radiant power from the body. (2) Determine the number of food Calories of energy (1 food Calorie = 4186 J) that is lost in one hour because of the net loss rate obtained in part (1). Metabolic conversion of food into energy replaces this loss.