(Answered) Suppose now that you wanted to determine the density of a

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Suppose now that you wanted to determine the density of a small yellow crystal to confirm that it is graphite. From the literature, you know that graphite has a density of 2.25 g/cm³. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCl₃ (d = 1.492 g/mL) and CHBr₃ (d = 2.890 g/mL)? (Note: 1 mL = 1 cm³.)

V(CHCl₃) = mL

V(CHBr₃) = mL

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