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student takes 116. g of BaCl2, and reacts it according to the following equation: 3BaCl2 + Al2(SO4)3 → 3BaSO4 + 2AlCl3 How many moles of AlCl3 are formed?
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Why do the instructions call for using a saturated solution of NaOH rather than one at lower concentration? Why can we ignored in the calculation of the concentration of NaOH?
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