Solve the recurrence relation a(n)=3a(n-1)+10a(n-2) with the initial conditions a(0)=0 and a(1)=2.
Solve the recurrence relation a(n)=3a(n-1)+10a(n-2) +12 with the initial conditions a(0)=0 and a(1)=2.
For a particular solution, try a(n)=C, a constant.