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Solve the following question given below:

Question I: An archer shoots an arrow at a 73.0 m distant target, the bull's-eye of which is at same height as the release height of the arrow. At what angle must the arrow be released to hit the bull's-eye if its initial speed is 37.0 m/s? (Although neglected here, the atmosphere provides significant lift to real arrows.)

Question II: There is a large tree halfway between the archer and the target with an overhanging branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch?

Explain your answers please for best answer! Thanks.

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  • Category:- Physics
  • Reference No.:- M91246257

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