Solve the each part of given question:

Question: Two parallel plates having charges of equal magnitude but opposite sign are separated by 27.0 cm. Each plate has a surface charge density of 35.0 nC/m². A proton is released from rest at the positive plate.

Part A: Determine the magnitude of the electric field between the plates from the charge density.

_______________________________kN/C

Part B: Determine the potential difference between the plates.

_______________________________V

Part C: Determine the kinetic energy of the proton when it reaches the negative plate.

_______________________________J

Part D: Determine the speed of the proton just before it strikes the negative plate.

_______________________________km/s

Part E: Determine the acceleration of the proton.

_______________________________m/s2 towards the negative plate

Part F: Determine the force on the proton.

_______________________________N towards the negative plate

Part G: From the force, find the magnitude of the electric field.

_______________________________ kN/C

Part H: How does your value of the electric field compare with that found in part (a)?

Please show me how you solve the above question.