Solve the all parts of given question:

Question: Consider a 100 mol mixture that is 76.0% methane (CH4) and 24.0% ethane (C2H6). To this mixture is added 24.0% excess air. Of the methane present, 93.70% reacts, 87.00% of which forms carbon dioxide (CO2), and the balance forms carbon monoxide (CO). Of the ethane present, 87.4% reacts, 87.00% of which forms carbon dioxide, and the balance forms carbon monoxide. What is the theoretical amount of oxygen required for the fuel mixture?

Part A: What amount of air is added to the fuel mixture?

Part B: How many moles of methane are present in the product gas?

Part C: How many moles of ethane are present in the product gas?

Part D: How many moles of carbon dioxide are present in the product gas?

Part E: How many moles of carbon monoxide are present in the product gas?

Part F: How many moles of water vapor are present in the product gas?

Part G: How many moles of oxygen are present in the product gas?

Part H: How many moles of nitrogen are present in the product gas?

Any help would be really appreciated! Thank you so much!