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Solve the all parts of given problem:

Problem: A capacitor is charged by a 100 V battery so that it has 3x10-5 C of charge on it. It has a layer of paper (dielectric constant of 4) that is 1.8 mm wide between the plates. The capacitor is removed from the battery, and then the paper is removed. Assuming the distance between the plates did not change,

Part I: What is the new potential energy stored in the capacitor?

Part II: What is the new electric field between the plates?

Please use as much detail as possible in answer!!!

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