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Solve the all parts of following question:

Question: A metal rod of length 76 cm and mass 1.79 kg has a uniform cross-sectional area of 7.7 cm². Due to a non uniform density, the center of mass of the rod is 22.2 cm from the right end of the rod. The rod is suspended in a horizontal position in water by ropes attached to both ends.

Part I: What is the tension in the rope closer to the center of mass?

Part II: What is the tension in the rope farther from the center of mass? (Hint: The buoyancy force on the rod effectively acts at the rod's center.)

Please show each step and the equations you used for the above question. Thanks!

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