Solve the all parts of following problem:

Problem: A parallel-plate capacitor has plates, each with an area of 1.5 cm2, that are separated by a distance of 0.25 mm. The capacitor is first is connected to a 12 V battery, and fully charged. For parts (a) through (d) below, the battery is then disconnected.

Part A: What is the charge on the capacitor?

C

Part B: If the plates are then pulled to a separation of 0.95 mm, what is the charge on the capacitor now?

C

Part C: What is the potential difference across the plates now?

V

Part D: How much work was required to pull the plates to their new separation?

J

Part E: Now go back to the first part of the problem with the capacitor connected to the battery and plate separation 0.25 mm. If the capacitor stays connected to the battery and the plates are pulled apart to a separation of 0.95 mm, what is the new potential difference across the capacitor?

V

Part F: For the situation in part (e), what will be the new charge on the capacitor?

C

Please explain how you came to your conclusion for above problem.