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Solve for the temperature if there are 1.231 L of 0.5387 moles of nitrogen at a pressure of 731.2 mm Hg.
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What is the calculation of the new temperature of a gas sample has an original volume of 740 ml when collected at 710 mm and 35 o C when the volume becomes 460 ml at 1.20 atm?
What are the symbol and name of the element whose average atoms have a mass very nearly half the mass of an average silicon atom?
What is the minimum amount of 6.0 M H 2 SO 4 necessary to produce 25.0g of H 2 (g) according to the reaction between aluminum and sulfuric acid? 2 Al(s) + 3 H 2 SO 4 (aq) --------> Al 2 (SO 4 ) 3 (aq) + 3 H 2 (g)
Carbon-carbon single bonds in organic molecules have energies about350. kJ/mol. What is the corresponding wavelength? Could UV lamps(248 nm) be used to break these bonds?
You will have a 500mL solution of salt water. From this you will take 10.0mL and place it on a balance. You find that the 10.0mL solution has a mass of 12.5 g. What is the density of the 500mL of salt water solution in g ...
The following sequence of reactions occurs in the commercial production of aqueous nitcric acid: 4NH3(g)+ 5O2(g) -> 4NO2 (g) + 6H2O(l) ΔH = -907 kJ 2NO(g) + O2(g) ? 2NO2(g) ΔH= -113 kJ 3NO2 + H2O(l) -> 2HNO3(aq) + NO(g) ...
A 41 kg person walking 5.6 km/hr requires 758 kJ of energy per hour. How much further does he have to walk to consume the addition energy contained i 320 g of ground beef relative to 320 g of broiled chicken? The energy ...
A metal slug weighing 16.32g is added to a flask with a volumeof 52.6 mL. it is found that, 40.2 g of methanol (d = 0.791 g/mL)must be added to the metal to fill the flask. What is the density of the metal in g/mL?
A chemist adds 370.0 mL of a 0.371M barium acetate (Ba(C2H3O2)2) solution to a reaction flask. Calculate the millimoles of barium acetate the chemist has added to the flask. Round your answer to 3 significant digits.
Barium Iodate (Ba(IO3)2) forms an equilibrium with is ions in solution. How does adding additional barium to the solution affect the Ksp of barium iodate. Explain.
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