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Question: The length of a 60 W, 240 ohms light bulb filament is 60 cm.

1) If the potential difference across the filament is 120 W, what is the strength of the electric field inside the filament? E = V/m

2) Suppose the length of the bulb's filament were doubled without changing its diameter or the potential difference across it. What would the electric field strength be in this case? E = V/m

3) Remembering that the current in the filament is proportional to the electric field, what is the current in the filament following the doubling of its length? I = A

4) What is the resistance of the filament following the doubling of its length? R = ohms

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