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Question: The distance from the cornea to the retina is 25 mm and an object infinitely far away is in focus on the retina. If an object is placed a distance of 1.0 m from the cornea, the eye accommodates by changing the radius of curvature of the posterior surface of the lens. Find the new radius of curvature. Assume that the changes are small enough that the distances between the surfaces remain unchanged.

Answer: -5.4 mm

Refractive indicies:

Air - 1.0003

Human Eye:

- Cornea - 1.38

- Aq. Humor - 1.34

- Lens - 1.41

- Vit. Humor - 1.34

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