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Question: A rocket starts from rest and moves upward from the surface of the earth. For the first 10.0 s of its motion, the vertical acceleration of the rocket is given by ay=(2.60m/s3)t, where the +y-direction is upward. What is the height of the rocket above the surface of the earth at t = 10.0 s ? What is the speed of the rocket when it is 255 m above the surface of the earth?

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