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Question: A proton with a speed of 2.0 × 105 m/s falls through a potential difference delta-V and thereby increases its speed to 4.0 × 105 m/s.

Part I: Through what potential difference did the proton fall?

I want help to find through what potential difference did the proton fall.

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  • Category:- Physics
  • Reference No.:- M91256800

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