Question a 30 mw laser lamda 545 nm shines on a cesium, Ask an Expert

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Question: A 3.0 mW laser (lamda = 545 nm) shines on a cesium photocathode (phi = 1.95 eV). Assume an efficiency of 10^-5 for producing photoelectrons (that is, 1 photoelectron is produced for every 105 incident photons).

Question 1: Determine the photoelectric current (nA).

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