Question- You want to make a solution buffered at pH = 4.80 using acetic acid (Ka= 1.75x10^-5). You add 16.4 g of sodium acetate to 500 ml of water ad want to adjust the pH with 1.00 M HCl,

1) How many ml of HCl do you need to add?
2) If you add 10.0 ml too much HCl, what is the pH?
3) When you are finished with part (a) you dilute the solution to 1.00 liter, what is the pH?

Solve the above problem and provide steps with explanation