Question- one drop has a volume of about 005 ml thus the, Ask an Expert

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Question- one drop has a volume of about 0.05 mL, thus the concentration of Cu2+ in the dilute half-cell is about (0.05mL/25mL)(0.1M)=2x10^-14 M. use Nernest equation E=-(0.0592/n) log [An+ Mdil] / [An+ Mconc] to calculate it at 298K.

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