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Question- Enough of a monoprotic acid is dissolved in water to produce a 0.0124 M solution. The pH of the resulting solution is 6.24. Calculate the Ka for the acid.

In this case, the inital 10-7 M H from water is not negligible. If [H ]iniital = 10-7 and [H ]final = 5.8 × 10-7, by how much did the concentration change? What does that say about how much A- was produced?

Give your answer with short explanation

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