Question- Air at a dry bulb temperature of 40 C and a wet bulb temperature of 20 C is first heated in a heater to a dry bulb temperature of 90 C. Then it is passed through a bed of apricot slices to dry them. The air exiting from the top of the apricot bed is at a dry bulb temperature of 60 C. It is then passed through a dehumidifier to reduce its relative humidity to 10%. Clearly show the various paths of the process on the psychrometric chart. The air velocity through the bed and the dehumidifier is 4 m/s and the cross-sectional diameter of the bed is 0.5 m.
1) Determine the amount of moisture removed in grams of water/second from the apricot bed.
2) Determine the amount of moisture removed in g-rams of water/second in the dehumidifier.
I just need a general explanation of it please- Thanks