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Question : A man stands on a platform that is rotating (without friction) with an angular speed of 1.1 rev/s; his arms are outstretched and he holds a brick in each hand. The rotational inertia of the system consisting of the man, bricks, and platform about the central vertical axis of the platform is 6.0 kg·m2. By moving the bricks the man decreases the rotational inertia of the system to 2.0 kg·m2.

 (a) What is the resulting angular speed of the platform?1 rev/s

 (b) What is the ratio of the new kinetic energy of the system to the original kinetic energy?2

(c) What provided the added kinetic energy? 

None of these is correct. the momentum of the platform the man moving the weights further away from his body the man pulling the weights closer to his body

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  • Category:- Physics
  • Reference No.:- M91231201

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