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Question- 500.0 mL of 0.120 M NaOH is added to 625 mL of 0.200 M weak acid (Ka = 6.95 × 10-5). What is the pH of the resulting buffer?

HA(aq)+OH-(aq)-------->H2O(l)+A-(aq)

Explain each steps for the above problem, I want help for above question

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