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Question- 1)

Cr2O7 2- + 6S2O3 2- + 14H+ ? 2Cr 3+ + 3S4O6 2- + 7H2O

a) Why is Cr6+ reduced in the following reaction?

b) Why is S2+ oxidized in the following reaction?

c) Why is Cr2O7 2- the oxidizing agent?

d) Why is S2O3 2- the reducing agent?

2)

14H+ + Cr2O72- + 3Ni ? 3Ni2+ + 2Cr3+ + 7H2O

a) Why is Ni the reducing agent

b) Why is Cr2O7 2- the oxidizing agent

Solve the above problem and provide steps with explanation

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  • Category:- Chemistry
  • Reference No.:- M91237388

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