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Question - A 75.0 mL volume of 0.0902 M Al(NO3)3 is diluted with water to a volume of 1.00 L. Then a 0.000100 L volume of this new solution was diluted with water to a volume of 0.00750 L. Calculate the molarity (M) of Al3+ in the final solution.

Molar Mass (g/mol)

Al(NO3)3 212.99

Al3+ 26.982

NO3- 62.004

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Category:- Chemistry
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