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Q. The kinetic energy of an electron 120 eV. Compute the de Broglie wavelength of electron.
λ = h / √2mE
λ = 6.626 X 10-34 / √ 2 X 9.1 X 10 -31 X 120 X 1.6 X 10-19
λ = 1.121 X 10 -10 m
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