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Q. In Young's double slit experiment, the width of the fringe obtained with light of wavelength 60000A is 2 mm. Calculate the fringe width if the entire apparatus is immersed in a liquid of refractive index 1.33

Data: λ = 6000 Å = 6 × 10-7 m; β = 2mm = 2 × 10^-³ m

μ = 1.33; β′ = ?

Solution: β′= Dλ′/ d = Dλ / μd

= β / μ

β′= 2 X 10 - 3/ 1.33

= 1.5 x 10-3 m (or) 1.5 mm

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