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Q. In an ideal transformer, the transformer ratio is 1:20.The input voltage and the input power are 6 V and 600 mW respectively. Compute the primary and the secondary currents.

Solution:

EpIp = 600 mW = 600 X 10^-3 W

Primary current Ip = EpIp / Ep = 600 X 10^-3/ 6 = 100 X 10^-3A

Ip / Is = 1 /20

Secondary current is = Ip X 20 = 2000 X 10 ^-3 A = 2 A

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Category:- Physics
Reference No.:- M9571310

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