Problem: Suppose you obtained the following data from doing the experiment described in the procedure. Complete the data table. The 25.00 mL of diluted HCI titrated in the experiments was prepared by diluting 25.00mL of a stock solution to 250.00 mL in a volumetric flask. The stock solution is the undiluted HCI.
|
Concentration of NaOH = 0.120M
|
|
|
Trial 1
|
Trial 2
|
Trial 3
|
|
Initial buret reading
|
6.24 mL
|
0.50 mL
|
1.48 mL
|
|
Final buret reading
|
26.06 mL
|
19.62 mL
|
21.00 mL
|
|
Volume of NaOH added
|
|
|
|
|
Moles of NaOH added
|
|
|
|
|
Moles of HCI reacted
|
|
|
|
|
Molarity of diluted HCI
|
|
|
|
|
Molarity of undiluted HCI
|
|
|
|
|
Average molarity of undiluted HCI
|
Find the molarity of the original HCI stock. Show your work as outlined in the calculations.