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Problem- When 18.5 moles of oxygen was reacted with 8.43 moles of acetylene,4.810 moles of water is formed in a 65% yield. How many moles of excess reactant remain? 2C2H2 + 5O2 (g) ----> 4 CO2 + 2H20

I have read my textbook moreover I still don't understand so please provide me a very condensed, simple to know answer?

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