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Problem- The reaction below takes place in a 250.0 mL flask at 23.8 C with SO2 having an initial pressure of 0.675 atm & O2 having an initial pressure of 0.335 atm

a) Before reaction, what is the total pressure in flask?

I got 1.01 atm

b) How many grams of SO3 are formed in the reaction? R = 0.082058

I used PV=nRT

n= (1.01atm) (.25L) / (0.082058) (296.95) = 0.01047 moles of gas not sure what step is next or if I have the correct formula.

I want to know how this is done please show all steps in detail

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  • Category:- Chemistry
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