Problem- the phosphate in a 4258 g sample of plant food was, Ask an Expert

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Problem- The phosphate in a 4.258 g sample of plant food was precipitated as Ag3PO4 through the addition of 50.00 mL of 0.0820 M AgNO3. The solid was filtered and washed. The collected washings were diluted to 250 mL. Titration of a 50mL sample of the diluted washings required 4.64 mL of 0.0625 M KSCN. Calculate the percent phosphate in the sample.

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