Problem- The lattice energy of rubidium chloride is the energy change accompanying the process- Rb+(g)+ Cl-(g)-->RbCl(s)

Calculate the lattice energy of RbCl using Hess Law and the following data-

1) Rb(s) --> Rb(g) H=86 kJ

2) Rb(g) --> Rb+(g) + e- H=409 kJ

3) Cl2(g) --> 2Cl(g) H=242 kJ

4) Cl(g) + e- --> Cl-(g) H=-355 kJ

5) Rb(s) +1/2 Cl2(g) --> RbCl(s) H=-435 kJ

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