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Problem- The equilibrium constant, K, for a neutralization reaction can be symbolized as Kn. Using Kw, Ka, and Kb values, determine Kn for the following reaction at 25° C.

NH3(aq)+ HCN(aq) reverse arrow sign NH+4 (aq) + CN- (aq)

Ka =6.2*10^-10

Kb = 1.8*10^-5

I want you to clarify the chemistry in this above problem.

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Category:- Chemistry
Reference No.:- M91227613

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