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Problem- The equilibrium constand for the reaction: AgBr(s)= Ag(aq)+Br(aq) is the solubility product constant, Ksp=7.7x10^13 at 25C. Calcualte delta G for the reaction when ag = 1x10^-2 M and Br= 1.0x10^-3 M. the answer is 40.6 kJ/mol. I am in need please provide me complete solution for the above problem so I can get right solution

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