Problem- show calculations for how you will prepare 250 ml, Ask an Expert

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Problem- Show calculations for how you will prepare 250 mL of 0.1 M AgNO3 solution from solid AgNO3 and water. Give the reagent amounts and units.

.1M x .250l = .025 mols

169.872 g mol

.025/169.872

0.00001177357

1x10-5 g ?

I have read my textbook in addition I at a halt don't understand thus please provide me a very strong and simple answer?

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