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Problem- I performed an experiment to determine the thermodynamic of Ca(OH)2 solubility in water. I have the following questions:

Calcium carbonate CaCO3 is less than 1/100th as soluble in water as Ca(OH)2 at room temperature. Carbon dioxide CO2 is a component of air that readily dissolves in water.

1.) Write a chemical equation representing the reaction aqueous Ca(OH)2 with dissolved CO2.

2.) Why should you boil the water for your high temperature determinations for several minutes before adding the solid Ca(OH)2?

3.) In what way, if any, is the temperature dependance of the molar solubility of Ca(OH)2 unusual?

Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?

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Category:- Chemistry
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