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Benzene (C6H6) as a gas burns in air at 200% theoretical air. In answering the following parts, you may assume the products of combustion are CO2, H2O, O2, and N2. You may also assume the following:

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Table 2.2 Heat of formation Δh-of in kJ/mole (at 25°C and 1 atm)a (abstracted from Reference [2])

Substance

Formula

State

Δh-of(kJ/mole)

Oxygen

O2

g

0

Nitrogen

N2

g

0

Graphite

C

s

0

Diamond

C

s

1.88

Carbon dioxide

CO2

g

-393.5

Carbon monoxide

CO

g

-110.5

Hydrogen

H2

g

0

Water

H2O

g

-241.8

Water

H2O

l

-285.9

Chlorine

Cl2

g

0

Hydrogen chloride

HCI

g

-92.3

Hydrogen cyanide

HCN

g

+135.1

Methane

CH4

g

-74.9

Propane

C3H8

g

-103.8

n-Butane

C4H10

g

-124.7

n-Heptane

C7H16

g

-187.8

Benzene

C6H6

g

+82.9

Formaldehyde

CH2O

g

-115.9

Methanol

CH4O

g

-201.2

Methanol

CH4O

l

-238.6

Ethanol

C2H6O

L

-277.7

Ethylene

C2H4

g

52.5

aValues for gaseous substances not in equilibrium at the standard state have been determined from liquid and the heat of vaporization.

a) For products and reactants at 25°C, calculate the heat of combustion of benzene in kJ/mol.

b) For the reactants at 25°C, compute the adiabatic flame temperature in Kelvin of benzene burning in air at 200% theoretical air.

c) For the reactants at 25°C, compute the adiabatic flame temperature in Kelvin of benzene burning in pure oxygen. Assume 200% of the required stoichiometric oxygen is supplied (molar basis). Is this a realistic temperature? Explain your answer.

d) Why is there a difference between b) and c) above? Give a physical argument.

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  • Reference No.:- M92015381

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