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Problem- A laboratory was assigned the job of determining the copper(II) ion concentration in thousands of water samples. To make these measurements an electrochemical cell was assembled that consists of a silver electrode, dipping into a 0.225 M solution of AgNO3, connected by a salt bridge to a second half-cell containing a copper electrode. The copper half-cell was then filled with one water sample after another, with the cell potential measured for each sample. In the analysis of two other water samples, cell potentials (Ecell) of 0.53 V and 0.64 V were obtained. Calculate the Cu2+ ion concentration in each of these samples.

[Cu2+] = when Ecell = 0.53 V

[Cu2+] = when Ecell = 0.64 V

Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?

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Category:- Chemistry
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