Q. The potential at location A is 370V. A positively charged particle is released there from rest and arrives at location B with the speed vB. The potential at location C is 607 V, and when released from rest from this spot, particle arrives at B with twice the speed it previously had, or 2 vB. Find out the potential at B.

Point A is located 0.259 m away from a charge of -2.11 x 10-9 C. Point B is located 0.487 m away from the charge. What is the electric potential difference VB - VA between these two points?

Charges of -q and +2q are set in place, with the distance of 3 m between them. A dashed line is drawn throughout the negative charge, perpendicular to the line between the charges. On the dashed line, at a distance L from the negative charge, there is as a minimum one spot where the total potential is zero. Find L.

Two identical point charges (q = +6.90 x 10-6 C) are fixed at opposite corners of a square whose sides have a length of 0.450 m. A test charge (q0 = -3.20 x 10-8 C), with the mass of 5.20 x 10-8 kg, is free from rest at one of the corners of the square. Determine the speed of the test charge when it reaches the center of square.