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ou have probably seen people jogging in extremely hot weather and wondered "Why?" As we shall see, there are good reasons not to do this! When jogging strenuously, an average runner of mass 67.0 kg and surface area 1.87 m2produces energy at a rate of up to 1330 W , 80.0 % of which is converted to heat.

The jogger radiates heat, but actually absorbs more from the hot air than he radiates away. At such high levels of activity, the skin's temperature can be elevated to around 33.0 oC instead of the usual 30.0 oC. (We shall neglect conduction, which would bring even more heat into his body.) The only way for the body to get rid of this extra heat is by evaporating water (sweating).

a) How much heat per second is produced just by the act of jogging?

b) How much net heat per second does the runner gain just from radiation if the air temperature is 40.0 oC (104 oF)? (Remember that he radiates out, but the environment radiates back in.)

c) What is the total amount of excess heat this runner's body must get rid of per second?

d) How much water must the jogger's body evaporate every minute due to his activity? The heat of vaporization of water at body temperature is 2.42x106 J/kg .

E) How many 750 mL bottles of water must he drink after (or preferably before!) jogging for a half hour? Recall that a liter of water has a mass of 1.00 kg .

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  • Category:- Physics
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