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problem 1: Imagine that a sample of 400 rental units shows that (i) the distribution of rents paid per month is not described by a normal distribution, (ii) that the mean rent of the sample is $755, and (iii) the standard deviation of the sample is $100.

a) Without seeing the distribution, can you compute the probability that the rent of a randomly selected unit will be greater than $800? If yes, find out the probability; if no, describe.

b) Without seeing the distribution, can you compute the probability that the mean rent of another sample of 400 units will be greater than $800? If yes, find out the probability; if no, describe.

c) Why is the answer to (b) only an estimate? (What two numbers about the whole population are you not sure of?)

problem 2: A study done at the University of Maryland (cited in Weiss, Introductory Statistics, 7th ed, 2005) measured the body temperatures of 93 healthy humans. On the frequency-histogram below, superimposed a normal probability-density curve by using the sample’s mean and standard deviation (98.12oF and  0.6468 oF respectively).

a) Construct a 99% confidence interval for the mean temperature of all healthy humans.

b) Interpret your interval in words.

c) Draw this confidence  interval in the space between the histogram and the boxplot on the next page. Point out both this sample’s mean, and the previously accepted value of 98.6oF.

d) You must now make a decision: the mean human-body-temperature is, or is not, 98.6oF. Which decision do you make? Briefly describe.

969_body temperatures curve.jpg

problem 3: Assume that you want to construct a 99% confidence interval for the mean body temperature for adult males. You want the interval’s margin of error to be to be 0.1 Fahrenheit degrees. You as well happen to know that the POPULATION’S standard deviation is 0.63 Fahrenheit degrees. Compute the size of the required sample.

problem 4
: An internal report issued by the marketing manager of a oil-change franchise claims that the mean number of miles between oil changes is for franchise customers is at least 3600 miles. One franchise owner suspects that the mean distance is actually less than 3600 miles. She collects a random sample of 10 customers, and finds out the distance each had driven between oil changes. She finds the given results.

3655     3734    3700    1946    3208
3311     2789    3920    3555    3902

x‾= 3372     s = 609

a) Make a stem-and-leaf diagram.

b) Does your stem-and-leaf diagram in (a) suggest that the distribution of distances is not normal? (For ex, is there any evidence that the distribution is skewed?)

c) Construct TWO 99% confidence intervals.

i) Use the z-tables.

ii) Use the t-tables.

d) Interpret your outcome in (ii) in words.

e) You now must decide: is the mean distance between oil changes 3600 miles, or not? Describe your reasoning.

f) Which (if either) of the confidence intervals in (c) is proper?

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  • Category:- Math
  • Reference No.:- M9789

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