Nitrate ion (NO2)^(-1) can be analyzed by creating an acidic solution of nitrite ion and adding excess iodide (I)^(-1) ions creating NO and I2. The I2 combines with excess (I)^(-1) to create (I3)^(-1). Using starch as an indicator, the (I3)^(-1) is titrated with (S2O3)^(-2) ion creating (S4O6)^(-2) ion and (I)^(-1) ion until the blue colour disappears. If a 0.9470 g sample was analyzed for nitrite ion using 29.00 mL of a 0.3000 mol/L Na2S2O3 solution, what is the mass of nitrite ion in the 0.9470 sample?
The ^ means upperscript and numbers written to the right of the chemical element is the downscript.