Morphine pkb 580 is the active ingredient in opium it is, Ask an Expert

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Morphine (pKb = 5.80) is the active ingredient in opium. It is used as an analgesic that directly acts on the central nervous system to alleviate pain. Morphine is on the DEA watch list as a schedule II drug under the controlled substances act.

Suppose a 25.00 mL sample of 0.300 M morphine solution is titrated with a 0.115 M standard HCl solution.

1. How many mL of HCl would be required to neutralize all of the base?

2. What is the pH of a 25.00 mL sample of morphine (before titration)?

3. What is the pH of the sample after adding 30.00 mL of 0.115 M HCl?

4. What is the pH of the solution at the equivalence point?

5. What is the pH of the solution after 5.00 mL of excess 0.115 M HCl is added?

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Category:- Chemistry
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