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Milk of Magnesia is actually a suspension (that's why instructions often mention shaking before use) of solid Mg(OH)2. 1.00 liter of solution of 0.055 moles of Mg2+ is held at a pH of 7.00. Would a precipitate form? If so, what fraction of the original 0.055 molar Mg2+ would precipitate at that pH? Ksp = 5.61 x 10-12

Mg(OH)2(s)  Mg2+(aq) + 2 OH-(aq)

  • 0%
  • 7%
  • 15%
  • 21%
  • 26%

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